Pq And Rs Are Long Parallel Conductors Separated By Certain Distance. M Is The Midpoint Between Them. The Net Magnetic Field At M Is B. Now The Current 2 A Is Switched Off. The Field At M Now Becomes

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Pq And Rs Are Long Parallel Conductors Separated By Certain Distance. M Is The Midpoint Between Them. The Net Magnetic Field At M Is B. Now The Current 2 A Is Switched Off. The Field At M Now Becomes

PQ and RS are long parallel conductors separated by a certain distance. M is the midpoint between them. The net magnetic field at M is B. Now the current 2 A is switched off. The field at M now becomes.

The problem statement is asking us to find the magnetic field at point M when the current in wire PQ is switched off. We can solve this problem by using the Biot-Savart law.

The Biot-Savart law states that the magnetic field due to a current-carrying conductor at a point is directly proportional to the current flowing through the conductor and inversely proportional to the distance between the point and the conductor.

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Let’s consider the magnetic field due to wire PQ first. Using the Biot-Savart law, we can write:

B_PQ = (μ_0 / 4π) * (2 I / d)

where μ_0 is the permeability of free space, I is the current flowing through wire PQ, and d is the distance between wire PQ and point M.

Similarly, we can find the magnetic field due to wire RS:

B_RS = (μ_0 / 4π) * (I / d)

where I is the current flowing through wire RS.

Since wire PQ and wire RS are parallel and carry currents in opposite directions, their magnetic fields at point M will be in opposite directions as well. Therefore, we can write:

B_net = B_PQ – B_RS

Substituting the values of B_PQ and B_RS, we get:

B_net = (μ_0 / 4π) * (2 I / d) – (μ_0 / 4π) * (I / d)

B_net = (μ_0 / 4π) * (I / d)

Now that we have found the magnetic field at point M due to wire PQ and wire RS when both are carrying currents, we can find the magnetic field at point M when the current in wire PQ is switched off.

When the current in wire PQ is switched off, only wire RS will be carrying current. Therefore, we can write:

B_new = (μ_0 / 4π) * (I / d)

which is equal to B_net.

Therefore, when the current in wire PQ is switched off, the magnetic field at point M will remain unchanged and will be equal to B_net.

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